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7⁷×_⁷∞(-42)⁷
6⁵×(⅓)⁵×4⁵∞_⁵
_⁷×0,5⁷×4⁷∞6⁷
Zakładam, że ∞ to jest =
7⁷×-6⁷=(-42)⁷
6⁵×(⅓)⁵×4⁵=8⁵
3⁷×0,5⁷×4⁷=6⁷
7⁷×(-6)⁷∞(-42)⁷
6⁵×(⅓)⁵×4⁵∞8⁵
3⁷×0,5⁷×4⁷∞6⁷