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6m+0.8m=6.8m
P1=4.8m*6.8m=32.64m2
P2=4m*6m=24m2
Pc=P1-P2
Pc=32.64m2-24m2=8.64m2
pole powierzchni sciezki wynosi 19,2 m
wydaje mi sie ze tak to powinno byc