Question

Witam.

a) 16²·(32( do potegi ½ ) · (¼)⁷)=?

b) log27 ∛3

Z góy dzieki ;)

Answer 1

a) 16²·(32( do potegi ½ ) · (¼)⁷)=  (2^4)² * 2^5 * (2^-2)^7 = 2^6 * 2^5 * 2^-14 = 2^-3

b) log27    ∛3  =  log 3³  ∛3  = 3 log 3 * ∛3 = 3^1/3  * 3 log 3 = 3^4/3   log 3