Witam proszę o szybkie rozwiązanie i rozpisanie pokolei jak robi się te obliczenia
1)
a1=3 q=2
-podaj wzor ogolny ciągu
-wyraz wyraz a2,a3,a4,a5
-oblicz S7
2) w ciagu geometrycznym a1=8 a2=4
-podaj wzor ogolny ciagu
-wyraż a3,a4.a5.a6
-oblicz s6
3) w ciagu arytmetycznym a1=1 a7=25
podaj wzor ogolny ciagu
oblicz a10 , s10
4) w ciagu arytmetycznym a1=3 r=-2 n=9
oblicz a9 i s9
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1.
a₁ = 3, q = 2
a)
an = a₁·q^(n-1)
an = 3·2^(n-1)
-------------------
b)
a₂ = 3·2 = 6
a₃ = 3·2² = 3·4 = 12
a₄ = 3·2³ = 3·8 = 24
a₅ = 3·2⁴ = 3·16 = 48
c)
Sn = a₁ · (1-q^n)/(1-q)
S₇ = 2 · (1-2⁷)/(1-2) = 3·(1-128)/(-1) = 3·127
S₇ = 381
2.
a₁₁ = 8, a₂ = 4
q = a₂/a₁ = 4/8 = ½
a)
an = a₁·q^(n-1)
an = 8·(½)^(n-1)
b)
a₃ = 8 · (½)² = 2
a₄ = 8 · (½)³ = 1
a₅ = 8 · (½)⁴ = ½
a₆ = 8 · (½)⁵ = ¼
c)
Sn = a₁ ·(1-q^n)/(1-q)
S₆ = 8 · [1 - (½)⁶)]/(1 - ½) = 8·(1 - 1/64)/(1/2) = 8·(63/64)/(1/2) = 8·2(63/64) = 1008/64
S₆ = 15¾
3.
a₁ = 1, a₇ = 25 ciąg arytmetyczny
a₇ = a₁ + 6r
25 = 1 + 6r
6r = 25 - 1
6r = 24 /:6
r = 4
a)
an = a₁ + (n-1)·r
an = 1 + (n-1)·4 = 1 + 4n - 4
an = 4n - 3
b)
a₁₀ = 1 + (10-1)·4 = 1 + 36
a₁₀ = 37
c)
Sn = n(a₁ + an)/2
S₁₀ = 10(1+37)/2 = 10·19
S₁₀ = 190
4.
a₁ = 3, r = -2 , n = 9, ciag arytmetyczny
a)
an = a₁ + (n-1)·r
a₉ = 3 + (9-1)·(-2) = 3 + (-16)
a₉ = -13
b)
S₉ = 9(3-13)/2 = 9(-10)/2
S₉ = -45
1. a1=3
q=2
wzór ogólny ciągu
an=a1*q^(n-1) = 3 * 2^(n-1)
a2= 3*2^1=6
a3=3*2^2=12
a4=3*2^3=24
a5=3*2^4=48
Sn=a1* [1-q^n]/[1-q]
S7=3*[1-2^7]/[-1] = 3*[-127]/[-1] = 381
2. a1=8
a2=a1*q
4=8*q
q=1/2
an=a1*q^(n-1) = 8*(1/2)^(n-1)
a3=8*(1/2)^2=2
a4=8*(1/2)^3=1
a5=8*(1/2)^4=1/2
a6=8*(1/2)^5=1/4
Sn=a1* [1-q^n]/[1-q]
S6=8*[1-(1/2)^6]/[1-1/2]=8*[63/64]/[1/2]=8*[126/64]=15,75
3, a1=1
a7=25
a7=a1+6r
25=1+6r
6r=24
r=4
an=a1+(n-1)r = 1 + (n-1)4 = 1+4n-4 = 4n-3
a10=4*10-3=37
S10=[a1+a10]/2 * 10 = [1+37]/2 * 10 = 190
4. a1=3
r=-2
a9=a1+8r=3-16=-13
S9=[2a1+(n-1)r]/2 * n = [6+8*(-2)]/2 * 9 = -45
Jak czegoś nie rozumiesz - pisz ;)