1. x3 + 5x2 + 2x - 8 = 0
W (1) = 0
schemat HORNERA:
1 5 2 -8
1 1 6 8
1 6 8 0
(x-1)(x2 + 6x + 8) = 0
delta = 36 - 32 = 4; pierwiastek z delty = 2
x1 = (-6-2)/2 = -4
x2 = (-6 + 2)/2 = -2
(x-1)(x+4)(x+2) = 0
x=1 lub x=-4 lub x=-2
3.
x3-x2+4x-4 = 0
x2(x-1) + 4(x-1) = 0
(x2 +4)(x-1) = 0
x=1
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1. x3 + 5x2 + 2x - 8 = 0
W (1) = 0
schemat HORNERA:
1 5 2 -8
1 1 6 8
1 6 8 0
(x-1)(x2 + 6x + 8) = 0
delta = 36 - 32 = 4; pierwiastek z delty = 2
x1 = (-6-2)/2 = -4
x2 = (-6 + 2)/2 = -2
(x-1)(x+4)(x+2) = 0
x=1 lub x=-4 lub x=-2
3.
x3-x2+4x-4 = 0
x2(x-1) + 4(x-1) = 0
(x2 +4)(x-1) = 0
x=1