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(a+b)³=a³+3a²b+3ab²+b³
zatem
a³+b³=(a+b)³-3a²b-3ab²=(a+b)³-3ab(a+b)=3³-3*1*3=27-9=18
(a+b)³= (a+b)³-3a²b-3ab²
(a+b)³-3ab(a+b)=3³-3*1*3
27-9=18
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