Wartość liczbowa wyrażenia : 2b ( 3b + 4b*2 + 6 ) - 3 (b*3 + b*2+b - 22 )
dla b = - 3 .
*2 - do potęgi 2
A. - 70
B. 70
C. - 69
D. -3
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
2b ( 3b + 4b*2 + 6 ) - 3 (b*3 + b*2+b - 22 ) = 6b*2 + 8b*3 + 12b - 3b*3 - 3b*2 - 3b + 66 = 3b*2 + 5b*3 + 9b + 66 = 3 * 9 + 5 * (-27) + 9 * (-3) + 66 = 27 - 135 - 27 + 66 = -69
odp: C czyli -69