w zadaniu 7 i 8 tylko do przykładu D
7d
2⁻³×2⁵-3³÷3⁴=(½)³×32-27÷81=⅛×32-27÷81=4-²⁷/₈₁=3⁵⁴/₈₁
8d
[(⅗)²-4⁻¹]=[⁹/₂₅-¼]⁻¹=[⁹/₂₅ - ²¹/₂₅]⁻¹=[-¹²/₂₅]⁻¹=[-²⁵/₁₂]=-2¹/₁₂
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7d
2⁻³×2⁵-3³÷3⁴=(½)³×32-27÷81=⅛×32-27÷81=4-²⁷/₈₁=3⁵⁴/₈₁
8d
[(⅗)²-4⁻¹]=[⁹/₂₅-¼]⁻¹=[⁹/₂₅ - ²¹/₂₅]⁻¹=[-¹²/₂₅]⁻¹=[-²⁵/₁₂]=-2¹/₁₂