w załączniku :)
1.
(x+1)/2 - (6x-1)/5 =( x+2)/3 - 1
(5x+5)/10 - (12x-2)/10 = (x+2)/3 - 3/3
(5x+5-12x+2)/10 = (x+2-3)/3
(-7x+7)/10 = (x-1)/3
(-7x+7)/10 - (x-1)/3 = 0
(-21x +21)/30 - (10x-10)/30 = 0
(-21x +21 - 10x +10 )/30 =0
(-31x +31)/30 = 0
-31x/30 = -31/30 : (-31/30)
x=1
sprawdzenie
(1+1)/2 - (6*1-1)/5 = (1+2)/3- 1
2/2 - (6-1)/5 = 3/3 - 1
1 - 5/5 = 1-1
1-1 = 1-1
0=0
L=P
2.
1/2 [1/2(1/2*x+1)+1]+1=2
1/2[1/4x+1/2+1]+1=2
1/8x+1/4+1/2+1=2
1/8x+2/8+4/8+8/8=2
1/8x= 2-14/8
1/8x= 16/8 - 14/8
1/8x= 2/8 /*8
x=2
1/2[1/2(1+1)+1]+1=2
1/2[1/2*2+1]+1=2
1/2[1+1]+1=2
1/2 *2 +1 =2
1+1=2
2=2
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1.
(x+1)/2 - (6x-1)/5 =( x+2)/3 - 1
(5x+5)/10 - (12x-2)/10 = (x+2)/3 - 3/3
(5x+5-12x+2)/10 = (x+2-3)/3
(-7x+7)/10 = (x-1)/3
(-7x+7)/10 - (x-1)/3 = 0
(-21x +21)/30 - (10x-10)/30 = 0
(-21x +21 - 10x +10 )/30 =0
(-31x +31)/30 = 0
-31x/30 = -31/30 : (-31/30)
x=1
sprawdzenie
(1+1)/2 - (6*1-1)/5 = (1+2)/3- 1
2/2 - (6-1)/5 = 3/3 - 1
1 - 5/5 = 1-1
1-1 = 1-1
0=0
L=P
2.
1/2 [1/2(1/2*x+1)+1]+1=2
1/2[1/4x+1/2+1]+1=2
1/8x+1/4+1/2+1=2
1/8x+2/8+4/8+8/8=2
1/8x= 2-14/8
1/8x= 16/8 - 14/8
1/8x= 2/8 /*8
x=2
sprawdzenie
1/2[1/2(1+1)+1]+1=2
1/2[1/2*2+1]+1=2
1/2[1+1]+1=2
1/2 *2 +1 =2
1+1=2
2=2
L=P