.W ukladzie współrzędnych narysuj wektor u i oblicz jego dlugosc wiedząc że a) u=[2,1] b)u=[-3,2] c)u=[-4 , -3] POMOZCIE SZYBKO PLIS
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a).![u=[2,1]\\ |u| = \sqrt{2^2 + 1^2} = \sqrt{5} u=[2,1]\\ |u| = \sqrt{2^2 + 1^2} = \sqrt{5}](https://tex.z-dn.net/?f=u%3D%5B2%2C1%5D%5C%5C+%7Cu%7C+%3D+%5Csqrt%7B2%5E2+%2B+1%5E2%7D+%3D+%5Csqrt%7B5%7D)
b).![u=[-3,2]\\ |u| = \sqrt{(-3)^2 + 2^2} = \sqrt{9 + 4} = \sqrt{13} u=[-3,2]\\ |u| = \sqrt{(-3)^2 + 2^2} = \sqrt{9 + 4} = \sqrt{13}](https://tex.z-dn.net/?f=u%3D%5B-3%2C2%5D%5C%5C+%7Cu%7C+%3D+%5Csqrt%7B%28-3%29%5E2+%2B+2%5E2%7D+%3D+%5Csqrt%7B9+%2B+4%7D+%3D+%5Csqrt%7B13%7D)
c).![u=[-4, -3]\\ |u| = \sqrt{(-4)^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5 u=[-4, -3]\\ |u| = \sqrt{(-4)^2 + (-3)^2} = \sqrt{16 + 9} = \sqrt{25} = 5](https://tex.z-dn.net/?f=u%3D%5B-4%2C+-3%5D%5C%5C+%7Cu%7C+%3D+%5Csqrt%7B%28-4%29%5E2+%2B+%28-3%29%5E2%7D+%3D+%5Csqrt%7B16+%2B+9%7D+%3D+%5Csqrt%7B25%7D+%3D+5)
rys. w zał