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c = 13 cm
b = ?
Z tw. Pitagorasa;
a² + b² = c²
b² = c² - a² = 13² - 12² = 169 - 144 = 25 cm²
b = √25 cm
b = 5 cm
Odp. D. 5 cm
b - dł 2 przyprostokątnej
c - dł przeciwprostokątnej
z tW Pitagorasa :
a^2 + b^2 = c^2
12^2 + b^2 = 13^2
144 + b^2 = 169
b^2 = 169 cm ^2- 144 cm^2
b^2 = 25 cm^2
b = 5 cm
spr.
12^2 + 5^2 = 13^2
144 + 25 = 169
169 = 169
L= P
Odp: D 5 cm