w trójkącie abc dane sa: |AC|=6 |AB|=9 k BAC=45 stopni.Oblicz pole tego trójkąta.
sin45* = h / 6
√2 / 2 = h / 6
2h = 6√2
h = 3√2 cm
P = 1/2 * a * h = 1/2 * 9 * 3√2 = 13,5√2 cm² -------- odpowiedź
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
sin45* = h / 6
√2 / 2 = h / 6
2h = 6√2
h = 3√2 cm
P = 1/2 * a * h = 1/2 * 9 * 3√2 = 13,5√2 cm² -------- odpowiedź