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Pozdrawiam, Adam
Cwl =2100 J/(kg* C) <ciepło wlasciwe lodu
Cww=4200 J/(kg*C) <cieplo wlasciwe wody
qt=333,7kJ/kg <cieplo topnienia lodu
T1=-10C
T2=0C
T3=20C
Qc=?
Q=m*Cw*ΔT <wzór na energie/ciepło
Q1=m*Cwl*(T2-T1)
Qt=qt *m
Q3=m*Cww*(T3-T2)
Qc=m*Cwl*(T2-T1) + qt *m + m*Cww*(T3-T2) = m*(Cwl*(T2-T1) + qt + Cww*(T3-T2))=
=1kg * [2100(J/kg*C)*(0-(-10C)) + 333,7 kJ/kg + 4200(J/kg*C)*(20C-0C))=
=1kg * [21000 J/kg + 333 700 J/kg + 84 000 J/kg]=
=1kg * 438 700 J/kg=
=438 700J