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IADI=3cm
IBCI=2cm
IBSI=6cm
IDSI=?
IBSI/IBCI+IBSI=IASI/IASI+IADI
IBSI/ICSI=IASI/IADI
6/2+6=X/3+X
6/8=X/3+X
8X=6(3+X)
8X=18+6X
8X-6X=18
2X=18
X=9
Odp.Odcinek IDSI wynosi 9 cm.
Spr.:
6/8=9/3+9
6/8=9/12
3/4=3/4