" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
CO2..........+H2.........= ........CO..........+.........H2O
stęż.pocz. 1..............5.....................0......................0
końc. 1 - x..........5 - x...................x......................x
K = [CO] [H2O]/{[CO2][H2]} = 1
[1-x][5-x] / [x][x] = 1
5-x-5x+x2 = x2 czyli 5-6x=0 czyli x=5/6= 0,8333 mola CO2 ulegnie przemianie
pozdrawiam
czarnadziura