pomiary doswiadczalne wykazaly, ze pewien roztwór jednoprotonowego kwasu ma pH=3 i @(alfa) =4% Obliczyc stezenie molowe roztworu
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pH= -log [H⁺]
3= -log [H⁺]
-3 = log [H⁺]
[H⁺]= 10⁻³= 0,001 mol/dm³
[H⁺]= α · C₀
0,001 = 0,04 · C₀
C₀ = 0,025 mol/dm³