W roztworze znajduje sie 4,82*10^22 jonow Ca^2+. Obj tego roztworu wynosi 150cm^3.Oblicz stezenie molowe.
Cm=n/V
n) 1 mol --- 6.02*10^23 jonów Ca2+
x --- 4.82*10^22 jonów Ca2+
x=0,08 mola
V) 1dm3 --- 1000cm3
y --- 150cm3
y=0.15dm3
Cm=n/v
Cm=0.08/0.15
Cm=0.533 [mold/dm3]
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Cm=n/V
n) 1 mol --- 6.02*10^23 jonów Ca2+
x --- 4.82*10^22 jonów Ca2+
x=0,08 mola
V) 1dm3 --- 1000cm3
y --- 150cm3
y=0.15dm3
Cm=n/v
Cm=0.08/0.15
Cm=0.533 [mold/dm3]