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y- ilość pięciozłotówek
1+x+y=41 |-1
1+2x+5y=150 |-1
x+y=40 |-y
2x+5y=149
x=40-y
2*(40-y)+5y=149
x=40-y
80-2y+5y=149
x=40-y
80+3y=149 |-80
x=40-y
3y=69 |:3
y=23
x=17
Odp. Dwuzłotówek było 17, a pięciozłotówek 23.
x - liczba 2zl
y - liczba 5xl
2x + 5y =149
x + y = 40
x = 40 -y
2 (40-y) +5y = 149
80 -2y+5y = 149
3y =69 => y = 23
x = 17