W ciągu geometrycznym81, -27, 9, -3 iloraz (q) jest równy?
a_{n+1}=a_{n}*q
a_{2}=a_{1}*q
-27=81*q /81
\frac{-27}{81}=q
q=-⅓
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a_{n+1}=a_{n}*q
a_{2}=a_{1}*q
-27=81*q /81
\frac{-27}{81}=q
q=-⅓