w ciagu geometrycznym a3= 2 i a5= 19. oblicz a1
prosze o szybka odp!
a₅=a₃*q²
19=2*q² /:2
q²=19/2
q=√(19/2)
a₃=a₁*q²
2=a₁*19/2 /:19/2
a₁=2:19/2
a₁=2*2/19
a₁=4/19
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a₅=a₃*q²
19=2*q² /:2
q²=19/2
q=√(19/2)
a₃=a₁*q²
2=a₁*19/2 /:19/2
a₁=2:19/2
a₁=2*2/19
a₁=4/19