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95/100 x 0,5l/1 = 0,475l - ilosc soli (policzone zostalo 95% z 0,5 litra)
5/100 X 0,5/1= 0,025l - ilosc H20
C%= ms(x100%)/mr
0,475(ms)x100%
______________ = 40%
0,5l + x
47,5
________ =40% /razy x
0,5l + x
47,5
______ = 40x /:40
0,5l
x= 47,5 1
_____ x ___
0,5l 40
x= 47,5
_____
20
x= 2,375l
mam nadzieje ze dobrze;)