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1200 x t = 48000 m3
t = 40 m
panjang sisi tegak adalah 50 m
48000 = 1/3 ×60² × t
48000 × 3 = 60² × t
144000 = 3600t
40 = t
t limas = 40 m
a = t limas
= 40 m
b = s : 2
= 60 m : 2
= 30 m
a² + b² = c²
40² + 30² = c²
1600 + 900 = c²
2500 = c²
√2500 = √c²
50 = c
t sisi tegak = c
= 50 m
Jadi panjang sisi tegaknya adalah 50 m.