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b) 3 - x = 2 + x
c) -(-5) + x= 5 - x
Rozwiąż równanie :
a) (√2x - 1)(√2x + 1) = (√2x - √5x)² + 2(√10x - 3) - (4 - x) |x √10
(20x-1)(20x+1)= (20x-2x)² + 2(x-3)- (4-x)
400x= 400x- 4x+ 2x-6-4+x
400x - 400x + 4x -2x -x= -6
x= -6
b) 3 - x = 2 + ..x.
c) -(.x..) + x= 5 - x
a) (√2x - 1)(√2x + 1) = (√2x - √5x)² + 2(√10x - 3) - (4 - x) |x √10
(20x-1)(20x+1)= (20x-2x)² + 2(x-3)- (4-x)
400x= 400x- 4x+ 2x-6-4+x
400x - 400x + 4x -2x -x= -6
x= -6