Usuń niewymierność z mianownika.Przykład e i f. daje najlepszy
e) (√2-1)/√3 = √3(√2 - 1)/3 = (√6 - √3)/3 = √3/√3 = 1
f) (2√3 + 5)/3√2 = √2(2√3 + 5)/6 = (2√6 + 5√2)/6
e)(√2-1)/√3=
=(√2-1)/√3 * √3/√3=
=(√6-√3)/3
f)(2√3+5)/3√2=
=(2√3+5)/3√2*3√2/3√2=
=(6√6+15√2)/18=
=⅓√6+⅚√2
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
e) (√2-1)/√3 = √3(√2 - 1)/3 = (√6 - √3)/3 = √3/√3 = 1
f) (2√3 + 5)/3√2 = √2(2√3 + 5)/6 = (2√6 + 5√2)/6
e)(√2-1)/√3=
=(√2-1)/√3 * √3/√3=
=(√6-√3)/3
f)(2√3+5)/3√2=
=(2√3+5)/3√2*3√2/3√2=
=(6√6+15√2)/18=
=⅓√6+⅚√2