Question

Usuń niewymierność z mianownika.

Answer 1

B)(8-√2)/5√2 =(8-√2)·√2 /(5√2·√2)=(8√2-2)/(5·2)=(8√2-2)/10=(4√2-1)/5

e)2√5/(√3+√7)=2√5(√3-√7)/(√3+√7)(√3-√7)=(2√15-2√35)/(3-7)=2(√15-√35)/-4=
(√35-√15)/2

f)(3√3+2√5)/(3√5-2√2)=(3√3+2√5)(3√5+2√2)/(3√5+2√2)(3√5-2√2)=(9√15+30+6√6+4√10)/(3√5)²-(2√2)² =(9√15+6√6+4√10+30)/(45-8)=(9√15+6√6+4√10+30)/(-37)= - (9√15-6√6-4√10-30)/37