Question

Uprość wyrażenie wymierne :

x^{2}-5x+6 : 2x^{2}-5x-3=

Answer 1

x² - 5x + 6 = (x - 2)(x  -3)

Δ = 25 - 24 = 1

x1 = (5 - 1) / 2 = 2

x2 = (5  +1) / 2 = 3

 

2x² - 5x - 3 = 2(x + 1/2)(x - 3)

Δ = 25 + 24 = 49

√Δ = 7

x1 = (5 - 7) / 4 = -1/2

x2 = (5  +7) / 4 = 3

 

 (x^{2}-5x+6 )/ (2x^{2}-5x-3) = [ (x - 2)(x  -3)] / [2(x + 1/2)(x - 3) ] = (x - 2) / (2x + 1)