Ułóż podane zwiąski ze wzrostem zawartości procentowej węgla :
C2H6, C3H8, C4H10, C5H12.
Proszę koniecznie na jutro :)
C-12
H-1
C2H6=80%
C3H8=81%
C4H10=82,7%
C5H12=83%
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C-12
H-1
C2H6=80%
C3H8=81%
C4H10=82,7%
C5H12=83%