Udowodnij, że jeśli a+b=1 i to
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(a²+b²)²=a⁴+2a²b²+b⁴
7²=a⁴+2a²b²+b⁴
49=a⁴+2a²b²+b⁴
(a+b)²=a²+2ab+b²
1²=a²+2ab+b²
1=a²+2ab+b²
a²+b²=7
1=7+2ab
2ab=-6
ab=-3
2ab*ab=2a²b²=-6*(-3)=18
49=a⁴+18+b⁴
a⁴+b⁴=31
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(a²+b²)²=a⁴+2a²b²+b⁴
7²=a⁴+2a²b²+b⁴
49=a⁴+2a²b²+b⁴
(a+b)²=a²+2ab+b²
1²=a²+2ab+b²
1=a²+2ab+b²
a²+b²=7
1=7+2ab
2ab=-6
ab=-3
2ab*ab=2a²b²=-6*(-3)=18
(a²+b²)²=a⁴+2a²b²+b⁴
49=a⁴+2a²b²+b⁴
49=a⁴+18+b⁴
a⁴+b⁴=31
PozDro