Udowodnij że 16⁵+2¹⁵ jest podzielne przez 33.
16⁵+2¹⁵ = (2⁴)⁵ + 2¹⁵ = 2²° + 2¹⁵ = 2¹⁵(1+2⁵) = 2¹⁵ * (1+32)= 2¹⁵ * 33
(16⁵+2¹⁵) : 33= (1048576+32768) : 33= 1081344:33=32768
16do potęgi 5=1048576
2 do potęgi 15=65536
65536+1048576=1114112/33=33760,(96)
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16⁵+2¹⁵ = (2⁴)⁵ + 2¹⁵ = 2²° + 2¹⁵ = 2¹⁵(1+2⁵) = 2¹⁵ * (1+32)= 2¹⁵ * 33
(16⁵+2¹⁵) : 33= (1048576+32768) : 33= 1081344:33=32768
16do potęgi 5=1048576
2 do potęgi 15=65536
65536+1048576=1114112/33=33760,(96)