proszę o pomoc matematyka klII gimnazjum zad10 str 103 na jutro
d)
{(x + y)/2 - x/3 = 4
{(x - y)/2 + y/3=-3
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f)
{(3x - 2)/3 -( 2x + y)/6 = x + 1/6
{x + y - (-x + y)/5 = 1/5 - 0,8x
/=ułamek
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d
(x+y)/2-x/3=4 /*6
(x-y)+y/3=-3 /*6
3(x+y)-2x=24
3(x-y)+2y=-18
3x+3y-2x=24
3x-3y+2y=-18
x+3y=24
3x-y=-18
x=24-3y
3*(24-3y)-y=-18
72-9y-y=-18
-10y=-18-72
y=90/10
y=9
x=24-3*9=24-27=-3
x=-3
y=9