Turunan pertama dari fungsi f(x) =5X ²÷⁵ adalah f' (x) . Nilai f'(32) adalah...
AkhmadRaumulfaro
![f(x)=5x^ \frac{2}{5} \\ f'(x) = \frac{2}{5} \times5x^ \frac{2}{5}^{-1} \\ f'(x) = 2x^ \frac{-3}{5} \\ f'(x)= \frac{2}{ \sqrt[5]{x^{3}} } \\ f'(32)= \frac{2}{ \sqrt[5]{32^{3}} } \\ f'(32)= \frac{2}{ \sqrt[5]{(2^{5})^{3}} } \\ f'(32)= \frac{2}{ \sqrt[5]{(2^{15})}} } \\ f'(32) = \frac{2}{2^{3}} \\ f'(32) = \frac{1}{4}](https://tex.z-dn.net/?f=f%28x%29%3D5x%5E+%5Cfrac%7B2%7D%7B5%7D+%5C%5C+f%27%28x%29+%3D+%5Cfrac%7B2%7D%7B5%7D+%5Ctimes5x%5E+%5Cfrac%7B2%7D%7B5%7D%5E%7B-1%7D+%5C%5C+f%27%28x%29+%3D+2x%5E+%5Cfrac%7B-3%7D%7B5%7D+%5C%5C+f%27%28x%29%3D+%5Cfrac%7B2%7D%7B+%5Csqrt%5B5%5D%7Bx%5E%7B3%7D%7D+%7D++%5C%5C+f%27%2832%29%3D+%5Cfrac%7B2%7D%7B+%5Csqrt%5B5%5D%7B32%5E%7B3%7D%7D+%7D+%5C%5C++f%27%2832%29%3D+%5Cfrac%7B2%7D%7B+%5Csqrt%5B5%5D%7B%282%5E%7B5%7D%29%5E%7B3%7D%7D+%7D+%5C%5C+f%27%2832%29%3D+%5Cfrac%7B2%7D%7B+%5Csqrt%5B5%5D%7B%282%5E%7B15%7D%29%7D%7D+%7D+%5C%5C+f%27%2832%29+%3D+%5Cfrac%7B2%7D%7B2%5E%7B3%7D%7D++%5C%5C+f%27%2832%29+%3D++%5Cfrac%7B1%7D%7B4%7D+ "f(x)=5x^ \frac{2}{5} \\ f'(x) = \frac{2}{5} \times5x^ \frac{2}{5}^{-1} \\ f'(x) = 2x^ \frac{-3}{5} \\ f'(x)= \frac{2}{ \sqrt[5]{x^{3}} } \\ f'(32)= \frac{2}{ \sqrt[5]{32^{3}} } \\ f'(32)= \frac{2}{ \sqrt[5]{(2^{5})^{3}} } \\ f'(32)= \frac{2}{ \sqrt[5]{(2^{15})}} } \\ f'(32) = \frac{2}{2^{3}} \\ f'(32) = \frac{1}{4}")
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izharulhaq78
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