Matematika
Nomor 1
f(x) = 3x - 1
f(-2) = 3(-2) - 1
= -7
f(-1) = 3(-1) - 1
= -4
f(0) = 3(0) - 1
= -1
f(1) = 3(1) - 1
= 2
f(2) = 3(2) - 1
= 5
range = {-7 , -4 , -1 , 2 , 5}
jawaban C
Nomor 2
= f(x) - g(x)
= x/(x+1) - x/(x-1)
= x(x - 1) - x(x + 1) / (x² - 1)
= (x² - x - x² - x) / (x² - 1)
= -2x / (x² - 1)
jawaban E
Nomor 3
(fog)(x) = (gof) (x)
f(g(x)) = g(f(x))
3g(x) - 4 = 2f(x) + p
3(2x + p) - 4 = 2(3x - 4) + p
6x + 3p - 4 = 6x - 8 + p
3p - p = 6x - 6x - 8 + 4
2p = -4
p = -2
jawaban D
Nomor 4
f(x) = 10 - x²
f(-1) = 10 - (-1)²
= 9
f(0) = 10 - 0²
= 10
f(1) = 10 - 1²
f(2) = 10 - 2²
= 6
f(3) = 10 - 3²
= 1
f(4) = 10 - 4²
= -6
range = {-6 , 1 , 6 , 9 , 10}
Nomor 5
(fog) (x) = f(g(x))
= 2g(x) - 1
= 2((x + 2) / (x - 1) - 1
= (2x + 4)/(x - 1) - (x-1)/(x-1)
= (x + 5) / (x - 1)
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Matematika
Nomor 1
f(x) = 3x - 1
f(-2) = 3(-2) - 1
= -7
f(-1) = 3(-1) - 1
= -4
f(0) = 3(0) - 1
= -1
f(1) = 3(1) - 1
= 2
f(2) = 3(2) - 1
= 5
range = {-7 , -4 , -1 , 2 , 5}
jawaban C
Nomor 2
= f(x) - g(x)
= x/(x+1) - x/(x-1)
= x(x - 1) - x(x + 1) / (x² - 1)
= (x² - x - x² - x) / (x² - 1)
= -2x / (x² - 1)
jawaban E
Nomor 3
(fog)(x) = (gof) (x)
f(g(x)) = g(f(x))
3g(x) - 4 = 2f(x) + p
3(2x + p) - 4 = 2(3x - 4) + p
6x + 3p - 4 = 6x - 8 + p
3p - p = 6x - 6x - 8 + 4
2p = -4
p = -2
jawaban D
Nomor 4
f(x) = 10 - x²
f(-1) = 10 - (-1)²
= 9
f(0) = 10 - 0²
= 10
f(1) = 10 - 1²
= 9
f(2) = 10 - 2²
= 6
f(3) = 10 - 3²
= 1
f(4) = 10 - 4²
= -6
range = {-6 , 1 , 6 , 9 , 10}
jawaban C
Nomor 5
(fog) (x) = f(g(x))
= 2g(x) - 1
= 2((x + 2) / (x - 1) - 1
= (2x + 4)/(x - 1) - (x-1)/(x-1)
= (x + 5) / (x - 1)
jawaban C