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2m = 16-10
m =6/2
m =3
(√(3y+I))²= 5² (kedua ruas kita kuadratkan)
3y + I = 25
3y. = 24
y. = 8
√(4y-7) = 3
(√(4y-7))²= 3² (kedua ruas dikuadratkan)
4y-7. = 9
4y. = I6
y. = 4
√(5a-8) = 3(kedua ruas kita kuadratkan)jd
5a-8. = 9
5a. = I7
a. = 3,4
√(2m+I0) = -4(kedua ruas dikuadratkan)
2m+I0. = I6
2m. = 6
m. = 3
√(6x-9) = 9 (kedua ruas dikuadratkan)
6x-9. = 8I
6x. = 90
x. = I5