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6b-4. = -64
6b. = -60
b. = -I0
³√(2y-5) = 3 (kedua ruas dipangkat 3)
2y-5. = 27
2y. = 32
y. = I6
2√(x-I). = 5 (kedua ruas dipangkat 2)
4(x-I). = 25
4x-4. = 25
4x. = 29
x. = 29/4
3√(y-2)= 9 (kedua ruas dipangkat 2)
9(y-2). = 8I
9y-I8. = 8I
9y. = 99
y. = II
√(3m+I2) -5 = 4
√(3m+I2) = 9 (kedua ruas dipangkat 2)
3m+I2. = 8I
3m. = 69
m. = 23
6-√(8m-I) = I0
6-I0 = √(8m-I)
-4 = √(8m-I) (kedua ruas dipangkat 2)
I6 = 8m-I
8m = I7
m. = I7/8
³√(7a-I) = 3 (kedua ruas dipangkat 3)
7a-I = 27
7a. = 28
a. = 4