" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
(³√(4y+I2))³=(-2)³
4y+I2 = -8
4y. = -20
y. = -5
³√(7m-8)= 3 (kedua ruas dipangkatkan 3)
7m-8 = 27
7m. = 35
m. = 5
³√(3y+7) +5 = 8
³√(3y+7) = 3 (kedua ruas dipangkatkan 3)
3y+7 = 27
3y. = 20
y. = 20/3
√(6a-I) +9 = 5
√(6a-I) = -4 (kedua ruas dipangkat 2)
6a-I = I6
6a. = I7
a. = I7/6
√(8b+4) -2 = 8
√(8b+4) = I0 (kedua ruas dipangkat 2)
8b+4. = I00
8b. = 96
b. = I2