Gaya normal
N = m.g - F₂.sin 60
Gaya gesek
f = μ.N
ΣF = m.a
F₁ - F₂.cos 60 - μ.(m.g - F₂.sin 60) = m.a
25 - 20.0,5 - 0,1. (2. 10 - 20. 0,5√3) = 2.a
25 - 10 - 0,1.(20-10√3) = 2.a
15 - 0,1. 2,68 = 2.a
14,7 = 2.a
a = 14,7/2 = 7,35 m/s²
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Gaya normal
N = m.g - F₂.sin 60
Gaya gesek
f = μ.N
ΣF = m.a
F₁ - F₂.cos 60 - μ.(m.g - F₂.sin 60) = m.a
25 - 20.0,5 - 0,1. (2. 10 - 20. 0,5√3) = 2.a
25 - 10 - 0,1.(20-10√3) = 2.a
15 - 0,1. 2,68 = 2.a
14,7 = 2.a
a = 14,7/2 = 7,35 m/s²