~Operasi Akar
[√(6√(6√(6√(...))))] / [√(8 : √(8 : √(8 : √( ..... ))))]
Telaah Secara Bertahap :
√(6√(6√(6√(...)))) = x
6 √(6√(6√(...))) = x²
x² - 6x = 0
(x + 0)(x - 6) → x = 6 ; x ≠ 0
√(8 : √(8 : √(8 : √( ..... )))) = x
8 / x = x²
x³ = 8
x = 2
Maka :
→ 6 / 2
→ 3
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~Operasi Akar
[√(6√(6√(6√(...))))] / [√(8 : √(8 : √(8 : √( ..... ))))]
Telaah Secara Bertahap :
√(6√(6√(6√(...)))) = x
6 √(6√(6√(...))) = x²
x² - 6x = 0
(x + 0)(x - 6) → x = 6 ; x ≠ 0
√(8 : √(8 : √(8 : √( ..... )))) = x
8 / x = x²
x³ = 8
x = 2
Maka :
[√(6√(6√(6√(...))))] / [√(8 : √(8 : √(8 : √( ..... ))))]
→ 6 / 2
→ 3