Question

Tolong ya soalnya buat bsk. Tks

Answer 1

16)
• y^2 +y -2 = 0
• (y +2)(y-1) = 0
• y = -2 | y = 1

y = -2(3)
y = -6
• (y +6) = 0

y = 1(3)
y = 3
• (y-3) = 0
(y +6)(y -3) = 0
• y^2 +3y -18 = 0 #B

18)
y^2 -(3y/2) = 5/2
y^2 -(3y/2) - (5/2) = 0
----------------------- ×2
• 2y^2 -3y -5 = 0
(x+1)(2x-5) = 0
x = -1 | x = 5/2

y1 > y2
y1 = 5/2
y2 = -1

•> 2(y1) - y2 = 2(5/2) - (-1)
~~~~~~~~~~ = 5 + 1
~~~~~~~~~~ = 6 #B

20)
d1 = 3p
d2 = p+2

d1 × d2 × 1/2 = 120
3p × (p+2) × (1/2) = 120
(3p^2 +6p)(1/2) = 120
3p^2 +6p = 240
3p^2 +6p -240 = 0
p^2 +2p - 80 = 0
(p-8)(p+10) = 0
p = 8 | p = -10

karena tdk boleh (-) , maka ambil p = 8

d1 = 3(8) = 24
d2 = (8+2) = 10

sisi = √([d1/2]^2 + [d2/2]^2)
~~ = √(12^2 + 5^2)
~~ = √(144 + 25
~~ = √169 = 13 cm #B