Question

No 2,4 tolong jawab secepatnya. tks (jawaban gak boleh ngasal!!)

Answer 1

No.2
y^2/3-y=0
y^2- 3y=0
y(y-3)=0
y=0 atau y=3
jwbn no.C {0,3}

no.4
4(x+1)^2-49=0
(2x+2)^2-49=0
(2x+2+7)(2x+2-7)=0
(2x+9)(2x-5)=0
x= -9/2= -4 1/2 atau
x= 5/2= 2 1/2
jwbn no.B

Answer 2

2. y^2/3 - y = 0
y^2/3 = y
y^2 = 3y
y^2 - 3y = 0
y (y-3) = 0
y = 0 atau y = 3
Hp = { 0 , 3 } ( C )

4. 4(x+1) - 49/(x+1) = 0
4(x+1) = 49/(x+1)
4(x^2 + 2x + 1) = 49
4x^2 + 8x + 4 = 49
4x^2 + 8x - 45 = 0
(4x - 10) (4x + 18) = 0
(2x - 5) (2x + 9) = 0
x= 5/2
= 2 1/2
x= -9/2
= -4 1/2
Hp = {2 1/2 , -4 1/2} ( B )

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