Question

No 6,8,10 tlg jawab secepatnya, tks (gak boleh ngasal)

Answer 1

6)
• (3-y)(2y-1) = 0

•> 3-y = 0
~~ -y+3 = 0
~~ -y = -3
~~ y = 3

•> 2y-1 = 0
~~ 2y = 1
~~ y = 1/2

Hp { 1/2 , 3 } #A

7)
• x^2 -5x +6 = 0
• (x-2)(x-3) = 0
• x = 2 | x = 3

Hp { 2, 3 } #D

8)
• 3x^2 +21x +36 = 0
• x^2 +7x +12 = 0
• (x+3)(x+4) = 0
• x = -3 | x = -4

Hp { -4, -3 } #B

9)
• 8 -3p(p+1) = -10
• 8 -3p^2 -3p +10 = 0
• -3p^2 -3p +18 = 0
• -p^2 -p +6 = 0
• -1(p^2 +p -6) = 0
• (-1)(p+3)(p-2) = 0
• (-p-3)(p-2) = 0
• p = -3 | p = 2

Hp { -3, 2 } #B

10)
• (1)/(2x-1) - (1)/(2x) = 1/6
• (2x - [2x-1])/(2x-1)(2x) = 1/6
• (2x -2x +1)/(4x^2 -2x) = 1/6
• (1)/(4x^2 -2x) = 1/6
• 6 = 4x^2 -2x
• 4x^2 -2x -6 = 0
• 2x^2 -x -3 = 0
• (2x-3)(x+1) = 0
• x = 3/2 | x = -1

Hp { -1, 3/2 } #A

Answer 2

6. A
8. B
10. A
sekian..