Question

Tolong jawab yaa pake rumusnya plisss ini sgt berarti jawabannya no. 3 yaa....

Answer 1

1.Panjang DE
segitiga AEC sebangun dengan segitiga BDC

AE/BD  = AC/BC = CE/DE
15/10 = 6 + BC/BC = 8 + DE/DE

15/10 = 8 + DE/DE
15DE = 80 + 10DE
15 DE - 10 DE = 80
5DE = 80
DE = 16 cm

2.Panjang BC
AE/BD  = AC/BC = CE/DE
15/10 = 6 + BC/BC = 8 + DE/DE

15/10 = 6 + BC/BC
15BC = 60 + 10 BC
15 BC - 10BC = 60
5BC = 60
BC = 12 cm

SEMOGA MEMBANTU :)