Jawaban:
4. nilai maksimumnya 9
5. nilai minimumnya 3
Penjelasan dengan langkah-langkah:
4. f(x) =x³-6x²+9
f'(x)= 3x²-12x (masing² dibagi 3)
0= x²-4x
0=x(x-4)
x= 0 atau x=4
f(0)=(0)³-6(0)²+9
=9
f(4)=(4)³-6(4)²+9
=-23
5. f(x)=2x³+3x²+3
f'(x)=6x²+6x
0=x²+x
0=x(x+1)
x=0 atau x=-1
f(0)=2(0)³+3(0)²+3
=3
f(-1)=2(-1)³+3(-1)²+3
=4
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Jawaban:
4. nilai maksimumnya 9
5. nilai minimumnya 3
Penjelasan dengan langkah-langkah:
4. f(x) =x³-6x²+9
f'(x)= 3x²-12x (masing² dibagi 3)
0= x²-4x
0=x(x-4)
x= 0 atau x=4
f(0)=(0)³-6(0)²+9
=9
f(4)=(4)³-6(4)²+9
=-23
5. f(x)=2x³+3x²+3
f'(x)=6x²+6x
0=x²+x
0=x(x+1)
x=0 atau x=-1
f(0)=2(0)³+3(0)²+3
=3
f(-1)=2(-1)³+3(-1)²+3
=4