Question

Tolong Fast jawab ya

Answer 1

³log (x+4) = ^9 log (26-x²), ³log (x+4) = ½ ³log (26-x²), 2 ³log (x+4) = ³log (26-x²) ³log (x+4)² = ³log (26-x²) (x+4)² = (26-x²) x²+8x+16 = 26-x² 2x²+8x-10 = 0 x²+4x-5 = 0 x = {-5,1}

Answer 2

Ingat : logb(x) = ^c log(x) / ^c log(b)

^3 log (x+4) = ^9 log (26 - x²)
^3 log (x+4) =  (^3 log (26 - x²)) / (^3 log 9)
^3 log (x+4) =  (^3 log (26 - x²)) / 2
2 x ^3 log (x+4) =  ^3 log (26 - x²)
^3 log (x+4)² =  ^3 log (26 - x²)
(x+4)² = (26 - x²)
x² + 8x + 16 = 26 - x²
x² + x² + 8x + 16 - 26 = 0
2x² + 8x - 10 = 0
x² + 4x - 5 = 0
(x+5)(x-1) = 0
x = -5  dan x = 1

nilai x yang memenuhi hanya x = 1, karena untuk x =-5 tidak bisa memenuhi ^3 log (x+4)

jadi, HS = {1}