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maaaf kalo salah
³log (x+4) = (1/2).³log (26-x²)
2.³log (x+4) = ³log (26-x²)
³log (x+4)² = ³log (26-x²)
x²+8x+16 = 26-x²
2x²+8x-10 = 0
x²+4x-5 = 0
(x+5)(x-1) = 0
x = -5 atau x = 1, syarat x > -4
maka x = 1................opsi A