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Cari gradien garis kmelalui titik (6, 0) dan (0, 3)
m = (y2 -y1) / (x2 - x1)
= (3 - 0) / (0 - 6)
= 3 / (-6)
= -1/2
garis m tegak lurus dengan daris k, maka :
m1.m2 = -1
-1/2 . m2 = -1
m2 = 2
gradien garis m adalah 2
Garis m melalui titik (6 , 0) dan titik (0, a)
m = (y2 - y1) / (x2 - x1)
2 = (a - 0) / (0 - 6)
2 = a / (-6)
a = 2 x (-6)
a = -12
maka, garis g memotong sumbu y di titik (0, -12)