Question

Tolong dibantu ya please :D

Answer 1

A₁ : A₂ = 4 : 1
h₁ = 5 m
h₂ = 1 m
v₁ = 36 km/jam = 10 m/s
P₁ = 9,1*10⁵ Pa

v₂ = ?
A₂ * v₂ = A₁ * v₁
1 * v₂ = 4 * 10
v₂ = 40 m/s = 144 km/jam

Hukum Bernoulli
P₁ + 1/2 * ρ * v₁² + ρ * g * h₁ = P₂ + 1/2 * ρ * v₂² + ρ * g * h₂
9,1*10⁵ + 1/2 *1000*10² + 1000*10*5 = P₂ + 1/2*1000*40² + 1000*10*1
P₂ = 200.000 Pa = 2*10⁵ Pa

ΔP = 9,1*10⁵ - 2*10⁵ = 7,1*10⁵ Pa

Answer 2

H1= 5 m
h2= 1 m
v1= 36 km/jam = 10 m/s
P1= 9,1 x 105. PaA1: A2= 4 : 1a) Kecepatan air pada pipa kecilPersamaan Kontinuitas :A1v1= A2v2(4)(10) = (1) (v2)v2= 40 m/sb) Selisih tekanan pada kedua pipaDari Persamaan Bernoulli :
P1+1/2ρv12+ ρgh1= P2+1/2ρv22+ ρgh2P1− P2=1/2ρ(v22−v12) + ρg(h2− h1)P1− P2=1/2(1000)(402− 102) + (1000)(10)(1 − 5)P1− P2= (500)(1500) − 40000 = 750000 − 40000P1− P2= 710000 Pa = 7,1 x 105Pac)
Tekanan pada pipa kecil
P1− P2= 7,1 x 1059,1 x 105− P2= 7,1 x 105P2= 2,0 x 105Pa