titik pusat dan jari-jari lingkaran dengam persamaan x² + y² + 8x - 2y - 47 = 0 adalah.... a. (-4,-1) dan 8 b. (-4,1) dan 8 c. (4,-1) dan 8 d. (4,1) dan 8 e. (8,2) dan 16
arsetpopeye
X^2 + y^2 + 8x - 2y - 47 = 0 A = 8, B = -2, C = -47 Pusat = (a, b) = (A/-2 , B/-2) = (8/-2 , -2/-2) = (-4, 1)
A = 8, B = -2, C = -47
Pusat = (a, b) = (A/-2 , B/-2) = (8/-2 , -2/-2) = (-4, 1)
Jari2 = r = √(a^2 + b^2 - C) = √(-4^2 + 1^1 - (-47)) = √(16 + 1 + 47) = √64 = 8