Please bantu di Jawab ya.... Question from @Bryan991

April 2019 2 38 Report

Please bantu di Jawab ya.

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$\left[\begin{array}{ccc}3a+5b&3\\2a&a+3b\\\end{array}\right] = \left[\begin{array}{ccc}7&a+2b\\-2&a+3b\\\end{array}\right]

2a = -2 , a = -1 

subs. a = -1 ke a+2b

-1 + 2b = 3

2b = 3+1

2b = 4

b = 2

subs. a = -1 dan b = 2 ke matriks M

M = \left[\begin{array}{ccc}3(-1)+5(2)&3\\2(-1)&(-1)+3(2)\\\end{array}\right]

= \left[\begin{array}{ccc}-3+10&3\\-2&-1+6\\\end{array}\right]

= \left[\begin{array}{ccc}7&3\\-2&5\\\end{array}\right]

$
$M^{T} = \left[\begin{array}{ccc}7&-2\\3&5\\\end{array}\right]$

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Bryan991 maksudnya??

Bryan991 jawabannya?

Bryan991 caranya?

AlfiantiRY itu udah caranya dek

DB45

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Kesamaan Matrik DanMatriks Transpos

M = N
.
2a = - 2 -->a = -1
.
3a+ 5b =7
3(-1) + 5b = 7
5b = 7+3
5b = 10
b = 2
.
a + 3b = (-1) + 3(2)
a + 3b = -1 +6
a + 3b = 5
.
Matriks M
7.....3
-2....5.

maka M^t
7.....-2
3....-5

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