Kemungkinan yang diinginkan
1. Mentah Mentah matang
2. Mentah matang matang
3. Matang Mentah mentah
P(1) = (2/12)(2/12)(10/12)=5/216
P(2) =(2/12)(10/12)(2/12)=5/216
P(3) =(10/12)(2/12)(2/12)=5/216
P(kejadian yang diinginkan) = P1+P2+ P3
= 5/72 (A)
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Kemungkinan yang diinginkan
1. Mentah Mentah matang
2. Mentah matang matang
3. Matang Mentah mentah
P(1) = (2/12)(2/12)(10/12)=5/216
P(2) =(2/12)(10/12)(2/12)=5/216
P(3) =(10/12)(2/12)(2/12)=5/216
P(kejadian yang diinginkan) = P1+P2+ P3
= 5/72 (A)