Question

Tolong bantuin kakak . soal limit fungsi

Answer 1

4a. lim(x->0)  {x²-3x)/(x²+ 2x)
= lim(x->0)  x(x-3)/x(x+2)
= lim(x->0) x-3/(x+2) = -3/2

4b. lim(x->0)  (2x³ + 5x + 4)/(x+2)
sub x = 0 --> (4)/(2) = 2

5a)
lim(x->4)  (4-x)/(2 - √x)
= lim(x->4) (2- √x)(2+√x)/ (2-√x)
= lim(x->4) (2 + √x)
x = 4  --> limit = 2 + √4= 4

5b)
lim(x->0)  x/(2 - √(4-x))
= lim(x->0) x (2 +√(4-x)) /(4 - (4-x))
= lim(x->0)  x(2+√(4-x)) /(x)
= lim(x->0)  2 + √(4-x)
x= 0 , limit = 2 +√4 = 4

3a.
lim(t-> 2) (t²- 5t + 6)/(t-2)
= lim(t->2)  (t-2)(t-3)/(t-2)
= lim (t->2) (t - 3)
t = 2 --> limit = 2-3 = - 1

3b. lim (t -> -2) (t+2)(t+3)/(t+2)
= lim(t->2) (t+3)
= 2+ 3
= 5